writing chemical formulas

    We have to find the equation of the line using the following formula`(y-y1)/(y2-y1)`=`(x-x1)/(x2-x1)`    Here (x1,y1) and (x2,y2) are the given two points.  Substitute the given points in the above formula we have to get the equation of the line.Example:(1, 3) and (4, 8) write the equation of the line that passing through the given two points by Method - 1Solution:Here x1 = 1 and y1=3 and x2=4 and y2=8The formula for equation of the line is `(y-y1)/(y2-y1)`=`(x-x1)/(x2-x1)`Substitute the x1, y1, x2 and y2 values in the above equation we have to get, `(y-3)/(8-3)`=`(x-1)/(4-1)`Simplifying this we can get, 3y=5x+4This is the equation of the line that passes through the given two points.